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The equation of such a line for the graph of y= x-10/3x^2+x+1 is blank

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Final answer:

The equation of such a line for the graph of y= x-10/3x^2+x+1 is 3x^2y + xy + y - x + 10 = 0.

Step-by-step explanation:

The equation of the line for the graph of y = (x - 10)/(3x^2 + x + 1) can be found by rearranging the given equation.

First, simplify the expression by combining like terms:

y = (x - 10)/(3x^2 + x + 1)

y = x-10/3x^2+x+1

Next, multiply both sides of the equation by the denominator to eliminate the fraction:

(3x^2 + x + 1)y = (x - 10)

Finally, distribute and rearrange the equation:

3x^2y + xy + y = x - 10

So, the equation of the line is 3x^2y + xy + y - x + 10 = 0.

User Manish S
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