Question

The second hand on Mr. Vidler's Alarm Clock is 6 cm long. Approximately how far does the tip travel in 5 minutes and 15 seconds? [Round your answer to the nearest tenth. Only type in the number, no units.]

Answer 1

3.28 cm

Explanation:

The calculation is given below:

we assume the following things

R denotes the radius of the circle

And, A denotes An arc

Now , the length of the arc is

L = (A ÷ 360°) × 2 × 3.14 × R

According to the question

R = 6 cm

Angle = 5 minutes and 15 seconds

The clock could complete its revolution in 60 minutes

Therefore

60 minutes = 360°

Also

1 min = 60 seconds

So

1 seconds = 1min ÷ 60seconds

Now for 15 seconds it is

= 15 seconds × (1 ÷ 60)

= (15 ÷ 60) min

= 0.25 min

And for 5 minutes and 15 seconds, it is

= 5 min + 0.25 min

= 5.25 min

Also

60 minutes = 360°

So,

1 minute = 360° ÷ 60min

Now For 5.25min

= (5.25min) × (360° ÷ 60min)

= 31.5°

Finally the length would be

L = (31.5° ÷ 360°) × 2 × 3.14 × 6cm

= 3.28 cm