Given that 10-√32 / √2 =a+b√2 where a and b are integers. Find the values of a and b.

Wrangler asked Feb 9, 2023

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Wrangler asked Feb 9, 2023

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17 votes

Answer:

a=-5, b=5

Explanation:

$(10-√(32))/(√(2)) \\ \\ =(10-5√(2))/(√(2)) \\ \\ =(10)/(√(2))-5 \\ \\ =5√(2)-5 \\ \\ \therefore a=-5, b=5$

Samgak answered Feb 14, 2023

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