Question

Find the points which divide the line segment joining the points (0, -3) and (7,1) in the ratio 2:3

internally and externally

Answer 1

Known two points, list function expression, use

`y-y_(0)=k(x-x_(0))`

`k= (y_(2) -y_(1\\))/(x_(2) -x_(1) )`

The function expression is

`y=(4)/(7)x-3`

It is known that the cross section of two points is 7, so the point of 2:3 is 14 / 5, that is, 0 + 14 / 5 is the abscissa of the point, which is substituted into the original equation to get y = - 7 / 5.

So the result is
`((14)/(5) ,-(7)/(5) )`