Question

Pls help dividing radicals !!!! Fast

Answer 1

After simplifying given problem we get

1.
`(√(42) )/(√(42) ) = 1`

2.
`\frac{\sqrt[3]{128}}{\sqrt[3]{2}}` = 4

3.
`(√(81) )/(√(9) ) = 3`

1. Given :-

`(√(42) )/(√(42) )`

Taking square root common

`\sqrt{(42)/(42) }`

When the number is divided by its own number we get an answer as 1.

So,

`√(1)`

The square root of 1 is 1.

= 1

2. Given:-

`\frac{\sqrt[3]{128}}{\sqrt[3]{2}}`

128 =
`2^7`

=
`\frac{\sqrt[3]{2^(7) }}{\sqrt[3]{2}}`

=
`\sqrt[3]{2^(7-1) }`

`=\sqrt[3]{2^(6) }`

`= \sqrt[3]{64}`

The cube root of 64 is 4

= 4

3. Given:-

`(√(81) )/(√(9) )`

Square root of 81 is 9

`= (9)/(3)`

By dividing 9 by 3 we get

= 3