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Balance the following chemical equation (if necessary):

SiCI4 (s) + H2O(I) → H4SiO4 (aq) + HCI(aq)

User Bboysupaman
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2 Answers

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\\ \sf\longmapsto SiCl_4+4H_2O\longrightarrow H_4SiO_4+4HCl

On reactant side

  • Si=1
  • H=8
  • Cl=4
  • O=4

On products side

  • Si=1
  • H=8
  • Cl=4
  • O=4
User Stepan Maksymov
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7 votes
7 votes

Answer: SiCl₄(s) + 4 H₂O(l) → H₄SiO₄(aq) + 4 HCl(aq)

Step-by-step explanation:
You can pretend there is an imaginary line splitting the chemical equation into two on the arrow to help balance the equation.
Balance out chlorine on both sides, add the coefficient 4 to HCl
now there are 4 chlorines on the left and the right side.
Then, balance out Hydrogen on both sides, add the coefficient 4 to H₂O
now, there are 4*2=8 hydrogens on the left and 4+4=8 hydrogens on the right.
Counting the total number of atoms on both sides of the arrow, the equation is balanced
1 Si = 1 Si
4 Cl = 4 Cl
4 O = 4 O
8 H = 8 H

User Kishor Prakash
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