Question

How much heat is absorbed when 3.70 mol
of A
reacts?

Answer 1

When 3.70 mol of ozone (O3) is formed, it absorbs approximately 529.1 kJ of heat, based on the given enthalpy of formation of 143 kJ/mol for O3.

Step-by-step explanation:

To find out how much heat is absorbed when 3.70 mol of ozone (O3) is formed, we can use the given enthalpy of formation (ΔH°) for O3. The ΔH° for 1 mole of O3 is 143 kJ (286 kJ / 2 mol). By using the molar enthalpy and the number of moles, the total heat absorbed can be calculated as follows:

ΔH for 3.70 mol of O3 = 3.70 mol × 143 kJ/mol

≈ 529.1 kJ (approximately)

Therefore, 3.70 mol of O3 will absorb approximately 529.1 kJ of heat when it reacts.