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1. (I) If a particle undergoes SHM with amplitude 0.18 m, what is the total distance it travels in one period?
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1. (I) If a particle undergoes SHM with amplitude 0.18 m,

what is the total distance it travels in one period?

User Hrishikesh Kadam
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1 Answer

10 votes

Final answer:

In simple harmonic motion (SHM), the total distance traveled by a particle in one time period is equal to twice the amplitude of the oscillation.

Step-by-step explanation:

In simple harmonic motion (SHM), the total distance traveled by a particle in one time period is equal to twice the amplitude of the oscillation. So, in this case, if the amplitude is 0.18 m, then the total distance traveled in one period would be 2 times the amplitude, which is 0.36 m.

User Beaslera
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