What is the heat change when 1.25 g of water vapor at 185.3C is cooled to 102.1C?The specific heat of steam is 2.02J/g C

QMFNP asked Oct 28, 2023

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QMFNP asked Oct 28, 2023

by QMFNP

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19 votes

Answer: -210.08 J

Step-by-step explanation:

Use the formula q = (m)(c)(ΔT)

q = (1.25)(2.02)(102.1-185.3)

q = -210.08 J

This is exothermic! Heat is lost.

RiesvGeffen answered Nov 3, 2023

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