190k views
0 votes
Domain:

Range:

x-intercept(s):

y-intercept:

Increase:

Decrease:

Min/Max:

Opens Up/Down:
Fill in the blank

Domain: Range: x-intercept(s): y-intercept: Increase: Decrease: Min/Max: Opens Up-example-1
User Jgerstle
by
8.4k points

1 Answer

5 votes

The domain of the curve is the set of all x-values it takes on, which in this case is the interval (1, 3). The range is the set of all y-values, which is (-4, 1). The x-intercepts are the points where the curve crosses the x-axis, which in this case there are none. The y-intercept is the point where the curve intersects the y-axis, which is -4. The curve first decreases, reaches a minimum point at (1, -4)

The curve described in the question starts in the third quadrant and passes through the point (-y, -4), then continues into the first quadrant passing through the points (x, 1), (1, y), and (3, y).

The domain of the curve is the set of all x-values it takes on, which in this case is the interval (1, 3).

The range is the set of all y-values, which is (-4, 1).

The x-intercepts are the points where the curve crosses the x-axis, which in this case there are none.

The y-intercept is the point where the curve intersects the y-axis, which is -4.

The curve first decreases, reaches a minimum point at (1, -4), and then increases.

So it decreases in the third quadrant, reaches a minimum in the first quadrant, and increases in the fourth quadrant.

The curve opens upward because the slope is positive.

The probable question may be:

The curve is from 3rd quadrant passing from point -y=-4 to first quadrant x=1,y=1,x=3 to 4th quadrant

Domain:

Range:

x-intercept(s):

y-intercept:

Increase:

Decrease:

Min/Max:

Opens Up/Down:

User Youval Bronicki
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories