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Domain:

Range:

x-intercept(s):

y-intercept:

Increase:

Decrease:

Min/Max:

Opens Up/Down:
Fill in the blank

Domain: Range: x-intercept(s): y-intercept: Increase: Decrease: Min/Max: Opens Up-example-1
User Jgerstle
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1 Answer

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The domain of the curve is the set of all x-values it takes on, which in this case is the interval (1, 3). The range is the set of all y-values, which is (-4, 1). The x-intercepts are the points where the curve crosses the x-axis, which in this case there are none. The y-intercept is the point where the curve intersects the y-axis, which is -4. The curve first decreases, reaches a minimum point at (1, -4)

The curve described in the question starts in the third quadrant and passes through the point (-y, -4), then continues into the first quadrant passing through the points (x, 1), (1, y), and (3, y).

The domain of the curve is the set of all x-values it takes on, which in this case is the interval (1, 3).

The range is the set of all y-values, which is (-4, 1).

The x-intercepts are the points where the curve crosses the x-axis, which in this case there are none.

The y-intercept is the point where the curve intersects the y-axis, which is -4.

The curve first decreases, reaches a minimum point at (1, -4), and then increases.

So it decreases in the third quadrant, reaches a minimum in the first quadrant, and increases in the fourth quadrant.

The curve opens upward because the slope is positive.

The probable question may be:

The curve is from 3rd quadrant passing from point -y=-4 to first quadrant x=1,y=1,x=3 to 4th quadrant

Domain:

Range:

x-intercept(s):

y-intercept:

Increase:

Decrease:

Min/Max:

Opens Up/Down:

User Youval Bronicki
by
8.8k points