Question

How many grams of oxygen are required to combine with 0.750 grams of nitrogen in the compound: N2O5?

Answer 1

2.14 g.

Step-by-step explanation:

Hello!

In this case, since the mole ratio between nitrogen and oxygen is 2:5 respectively, we realize we first need the moles of nitrogen given it's atomic mass (14.01 g/mol):

`n_N=0.750g*(1mol)/(14.01g)=0.0535molN`

Now, we calculate the moles of oxygen:

`n_O=0.0535molO*(5molO)/(2molN)=0.134molO`

Then, we compute the moles of oxygen given its atomic mass (16.00 g/mol):

`m_O=0.134molO*(16.00gO)/(1molO_2) \\\\m_O=2.14gO`

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