Final answer:
To calculate the enthalpy change (ΔHo) for the reaction, we can use Hess's Law to manipulate the given reactions and obtain the desired equation. By reversing equation 1 and multiplying equation 2 by 2, we can add the two equations together to calculate the enthalpy change for the desired reaction, which is -345.0 kJ/mol.
Step-by-step explanation:
We can use Hess's Law to calculate the enthalpy change (ΔHo) for the reaction: Fe2O3 + 3 CO → 2 Fe + 3 CO2. Given the following reactions and their enthalpy changes:
- 4 Fe + 3 O2 → 2 Fe2O3 ΔHo = -1650 kJ/mol
- CO + ½ O2 → CO2 ΔHo = -280 kJ/mol
We need to manipulate these equations to obtain the desired equation. We can reverse equation 1 and multiply equation 2 by 2 to balance the number of CO and Fe2O3:
- 2 CO → 2 C + O2 ΔH = 221.0 kJ/mol
- 2 C + O2 → 2 CO2 ΔH = -566.0 kJ/mol
Now we can add these two equations together:
2 CO + O2 → 2 CO2 ΔHo = 221.0 kJ/mol + (-566.0 kJ/mol) = -345.0 kJ/mol
Therefore, the ΔHo for the given reaction is -345.0 kJ/mol.