Question

If 10.0 liters of oxygen at STP are heated to 785.15 °K, what will be the new volume of gas if the pressure is also increased to 102.6 Kpa of pressure?

Answer 1

Answer: The new volume of gas is 28.5 L

Step-by-step explanation:

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 1.00 atm (at STP)

`P_2` = final pressure of gas = 102.6 kPa = 1.01 atm (1 kPa= 0.0098 atm)

`V_1` = initial volume of gas = 10.0 L

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`273.15K` (STP)

`T_2` = final temperature of gas =
`785.15K`

Now put all the given values in the above equation, we get:

`(1.00* 10.0)/(273.15)=(1.01* V_2)/(785.15)`

`V_2=28.5L`

The new volume of gas is 28.5 L