Final answer:
In a reaction between Sn and Ag, Sn is the anode where oxidation occurs and Ag is the cathode where reduction occurs, so Sn(s) is the anode and Ag(s) is the cathode.
Step-by-step explanation:
The anode in a galvanic cell is the electrode where oxidation occurs, while the cathode is the electrode where reduction occurs. In the case of a reaction between Sn(s) and Ag(s), the anode is Sn(s) and the cathode is Ag(s). This means that Sn(s) undergoes oxidation at the anode, while Ag(s) undergoes reduction at the cathode.
In a reaction between tin (Sn) and silver (Ag), we determine which solid is the anode and which is the cathode based on the redox processes that occur at each electrode in an electrochemical cell. The anode is the electrode where oxidation occurs (loss of electrons), and the cathode is the electrode where reduction occurs (gain of electrons). From the given information, we know that in a standard galvanic cell where Sn and Ag are used, Sn acts as the anode because it gets oxidized from Sn(s) to Sn2+ (aq), and Ag acts as the cathode because Ag+ (aq) gets reduced to Ag(s). Therefore, the correct answer is a) Sn(s) is the anode, and Ag(s) is the cathode.