Final answer:
After calculating the OH- concentration as 1.6 × 10-2 M and determining the pOH as 1.80, the pH of the 8.0 × 10-3 M Ca(OH)2 solution at 25.0°C is found to be 12.20, which is not listed among the provided options.
Step-by-step explanation:
The question provided is related to calculating the pH of an aqueous solution of Ca(OH)2. Given a concentration of 8.0 × 10-3 M, we start by calculating the concentration of OH- ions in the solution. Since Ca(OH)2 dissociates completely into Ca2+ and 2 OH-, the [OH-] will be 2 × 8.0 × 10-3 M = 1.6 × 10-2 M. The pOH is calculated using the formula pOH = -log[OH-], which results in a pOH of 1.80. The pH is then determined using the formula pH = 14 - pOH, which gives us a pH of 12.20. No match is found in the options a) to d), thus the correct answer is e) none of these.