Question

A water sample contains the pollutant chlorobenzene with a concentration of 14 ppb (by mass). What volume of this water contains 4.66 × 10^2 mg of chlorobenzene (Assume a density of 1.00 g/mL)?

Answer 1

To determine the volume of water containing 4.66 × 10^2 mg of chlorobenzene, convert the mass to grams and use the density of water to convert to milliliters. The volume is 0.466 mL.

Step-by-step explanation:

To calculate the volume of water containing 4.66 × 10^2 mg of chlorobenzene, we need to consider the concentration of chlorobenzene in the water sample. Given that the concentration of chlorobenzene is 14 ppb (parts per billion) by mass, we can convert the mass of chlorobenzene to volume using the density of water.

First, we need to convert the mass of chlorobenzene to grams by dividing the given mass by 1000.

So, 4.66 × 10^2 mg = 0.466 g.

Next, we can use the density of water, which is given as 1.00 g/mL, to convert grams to milliliters.

Therefore, the volume of water containing 0.466 g of chlorobenzene is 0.466 mL.