Question

An aqueous NaCl solution is made using 115g of NaCl diluted to a total solution volume of 1.05 L.

-Calculate the molarity of the solution.
-Calculate the molality of the solution. (Assume a density of 1.08 g/mL for the solution.)
-Calculate the mass percent of the solution. (Assume a density of 1.08 g/mL for the solution.)

Answer 1

The molarity of the NaCl solution is 2.13 M, the molality is 0.93 m, and the mass percent is 9.8%.

Step-by-step explanation:

The molarity of the NaCl solution can be calculated using the formula mass of the solute divided by the volume of the solution. In this case, the mass of NaCl is 115g and the total volume is 1.05L. Therefore, the molarity of the solution is:

Molarity = (115g / 58.44g/mol) / 1.05L = 2.13 M

The molality of the solution can be calculated using the formula mass of the solute divided by the mass of the solvent. The mass of NaCl is 115g and the mass of the solvent can be calculated by multiplying the density of the solution by the total volume:

Mass of solvent = density x volume = 1.08 g/mL x 1.05 L = 1.13 kg

Therefore, the molality of the solution is:

Molality = (115g / 58.44g/mol) / 1.13 kg = 0.93 m

The mass percent of the solution can be calculated using the formula mass of the solute divided by the mass of the solution, multiplied by 100:

Mass percent = (115g / (115g + 1.05L x 1.08g/mL)) x 100 = 9.8%