Final answer:
The magnetic force acting on the proton is approximately 6.7 × 10^-16 N.
Step-by-step explanation:
To calculate the magnetic force on the proton, we can use the equation:
F = qvBsinθ
where F is the force, q is the charge of the proton, v is the velocity of the proton, B is the magnetic field strength, and θ is the angle between the proton's velocity and the magnetic field.
Given that the proton has a charge of 1.60 × 10-19 C, a velocity of 7.0 km/s (which can be converted to 7000 m/s), and a magnetic field strength of 0.60 T, and since the proton's velocity is perpendicular to the magnetic field (θ = 90°), we can plug these values into the equation:
F = (1.60 × 10-19 C)(7000 m/s)(0.60 T)(sin 90°)
Calculating this gives us:
F ≈ 6.7 × 10-16 N.
Therefore, the magnitude of the magnetic force that acts on the proton is approximately 6.7 × 10-16 N.