Final answer:
The energy stored on a capacitor can be calculated using the formula: E = (1/2) * C * V^2. In this case, the capacitor is charged to 2 mC and connected to a 12-V battery. The correct answer is D. 24 mJ.
Step-by-step explanation:
The energy stored on a capacitor can be calculated using the formula:
E = (1/2) * C * V^2
Where E is the energy, C is the capacitance, and V is the voltage across the capacitor.
In this case, the capacitor is charged to 2 mC (milliCoulombs) and connected to a 12-V battery. We can assume that the capacitance is given as:
C = 2 mC / 12 V = 0.167 mF
Plugging in the values, we can calculate the energy as:
E = (1/2) * 0.167 mF * (12 V)^2 ≈ 1.44 mJ
Therefore, the correct option is C. 144 mJ.