Question

A 3.0-mC point charge and a 10.0-mC point charge are initially extremely far apart. How much work does it take to bring the 3.0-mC point charge to a position 6.0 mm frin tge 10.0-mC point charge?

A. 90 J
B. 30 J
C. 7.5 J
D. 45 J

Answer 1

The work done in bringing a point charge from one point to another is given by the equation: W = q(Vf - Vi). In this case, we have a 3.0-mC point charge and a 10.0-mC point charge. Initially, the charges are extremely far apart, so the initial potential is considered negligible. Bringing the 3.0-mC point charge to a position 6.0 mm from the 10.0-mC charge means the final potential is non-zero.

Step-by-step explanation:

The work done in bringing a point charge from one point to another is given by the equation:

W = q(Vf - Vi)

where W is the work done, q is the charge, and Vf and Vi are the final and initial potentials, respectively.

In this case, we have a 3.0-mC point charge and a 10.0-mC point charge. Initially, the charges are extremely far apart, so the initial potential is considered negligible. Bringing the 3.0-mC point charge to a position 6.0 mm from the 10.0-mC charge means the final potential is non-zero. Therefore, the work done can be calculated using the equation above with the given values.