Question

A squirrel pulls a 8.7 kg bag of acorns along the ground with a constant force of 80 N. If the force of friction opposing this sliding is 32 N. what will be the acceleration of the bag of acorns?​

Answer 1

`a=5.51\ m/s^2`

Step-by-step explanation:

Given that,

The mass of a bag of acorns, m = 8.5 kg

The force acting on the bag = 80 N

The force of friction = 32 N

We need to find the acceleration of the bag of acorns.

Net force acting on it is = 80 N - 32 N

= 48 N

Let a be the acceleration of the bag of acorns. So,

F = ma

`a=(F)/(m)\\\\a=(48)/(8.7)\\\\a=5.51\ m/s^2`

So, the acceleration of the bag of acorns is
`5.51\ m/s^2`.