Final answer:
The mass of chlorine that can be formed from 50.0 g of sodium chloride is calculated to be 30.31 g, using the molar masses of NaCl and Cl2 and the stoichiometry from the balanced chemical equation.
Step-by-step explanation:
To calculate the mass of chlorine (Cl2) that can be formed from 50.0 g of sodium chloride (NaCl), you would need to use stoichiometry. Based on the balanced chemical reaction provided, 2 moles of NaCl produce 1 mole of Cl2. First, you calculate the number of moles of NaCl using its molar mass (58.44 g/mol).
Number of moles of NaCl = 50.0 g / 58.44 g/mol = 0.855 moles. Then, using the stoichiometry of the balanced chemical equation, we calculate the moles of Cl2 produced:
0.855 moles NaCl x (1 mole Cl2 / 2 moles NaCl) = 0.4275 moles Cl2.
Finally, using the molar mass of Cl2 (which is approximately 70.90 g/mol), we calculate the mass of chlorine produced:
Mass of Cl2 = 0.4275 moles x 70.90 g/mol = 30.31 g.
Therefore, the mass of chlorine that can be formed from 50.0 g of sodium chloride is 30.31 g.