Question

What wavelength of light is emitted in nm from an electron in a hydrogen atom moving from the n=4 to n=1 energy state?

Answer 1

Step-by-step explanation:

n1 = 1 and n2 = 4

from the formula

let v be walength

1/v = 1.097 x 10^7(1/n1 ^2 - 1/n2^2)

= 1.097 x 10^7(1/1 - 1/4^2)

= 1.097 x 10^7 x 0.9375

1/v = 1.0287 x 10^7

to find v

v = 1/1.0287 x 10^7

v = 9.72 x 10 ^-8

Wavelength = 97.2nm