Final answer:
The larger square has dimensions of 4 centimeters, and one possible set of dimensions for the rectangle with a perimeter of 36 centimeters is 8 centimeters x 10 centimeters.
Step-by-step explanation:
To find the dimensions of the larger rectangle, we need to determine the scale factor. The problem states that the dimensions are twice the first square, so the scale factor is 2. Therefore, the side length of the larger square is twice the side length of the first square, which is 2 centimeters x 2 = 4 centimeters.
Next, we need to find one possible set of dimensions for the rectangle with a perimeter of 36 centimeters. Since the rectangle has a perimeter of 36 centimeters, the sum of its sides is 36/2 = 18 centimeters.
Let's assume the length of the rectangle is 8 centimeters. This means the width of the rectangle is 18 - 8 = 10 centimeters. Therefore, one possible set of dimensions for the rectangle with a perimeter of 36 centimeters is 8 centimeters x 10 centimeters.