Question

A kettle with 2 kW of heating element contains water with heat capacity of 5000 J per° Celsius while the water is heating up from 8°C to 88°C 150 kJ is registered and warming up the kettle size and the surrounding air how much energy will the heating element have released?

Answer 1

The heat capacity of the kettle is 5000 J/°C. The heating element will have released 400,000 joules of energy.

Step-by-step explanation:

The heat capacity of an object is the amount of heat energy required to raise its temperature by 1 degree Celsius. In this case, the kettle contains water with a heat capacity of 5000 J/°C. To calculate the heat energy released by the heating element, we can use the equation:

Energy released = heat capacity × change in temperature.

Substituting the values, we get:

Energy released = 5000 J/°C × (88°C - 8°C) = 400,000 J.

Therefore, the heating element will have released 400,000 joules of energy.