Question

Dr. Octopus is chasing Spider-man. Spider-man reaches a wall and starts climbing up at a speed of 3 m/s. When Spider-man starts his climb, Dr. Octopus is 102 m from the base of the wall and is running toward it at a speed of 5 m/s. How many seconds after Spider-man starts climbing will Dr. Octopus be closest to Spider-man? (This is when Dr. Octopus intends to grab Spider-man with his long arms.

Answer 1

Dr. Octopus will be closest to Spider-man 17 seconds after Spider-man starts climbing.

Step-by-step explanation:

To determine when Dr. Octopus will be closest to Spider-man, we need to find the time it takes for their distances to be the same. We can set up an equation using the distances and velocities of Spider-man and Dr. Octopus.

Spider-man's equation: distance = speed x time

Dr. Octopus's equation: distance = initial distance - speed x time

Setting the two equations equal to each other, we can solve for time. Rearranging the equation gives: speed x time = initial distance - speed x time

Simplifying the equation gives: 2 x speed x time = initial distance

Substituting the given values: 2 x 3 m/s x time = 102 m

Solving for time gives: time = 102 m / (2 x 3 m/s) = 17 s

Therefore, Dr. Octopus will be closest to Spider-man 17 seconds after Spider-man starts climbing.