Question

A deer jumps at 3.75 m/s from flat ground at a 46.3° angle. How long does it take to reach its maximum height?

(Unit = s)

Answer 1

To find the time taken by the deer to reach its maximum height, we can use the equation for the vertical component of velocity. The deer takes 0.725 seconds to reach its maximum height.

Step-by-step explanation:

v = u + gt

Where:

v is the final velocity (0 m/s at maximum height),

u is the initial velocity in the vertical direction (3.75 m/s multiplied by the sine of the launch angle),

g is the acceleration due to gravity (-9.8 m/s^2), and

t is the time taken.

Setting v to 0 and solving for t:

0 = u - gt

gt = u

t = u / g

Substituting the values:

t = (3.75 m/s × sin(46.3°)) / 9.8 m/s^2

Using a calculator:

t = 0.725 s