Final answer:
The correct option for the slope of a straight line in a natural logarithm vs. time plot is D. (ln C1 - ln C0)/(t1 - t0), representing the slope of the line that best fits our data points in reaction kinetics.
Step-by-step explanation:
The question is asking us to determine the slope of a straight line given some options. The slope of a straight line in the context of a plot of natural logarithm values (ln) versus time (t) is calculated using the formula for the slope, which is the change in y divided by the change in x.
Therefore, the correct option is D. (ln C1 - ln C0)/(t1 - t0), which represents the change in the natural logarithm of concentration over the change in time, effectively giving us the slope of the line that best fits our data points for a reaction kinetics analysis.
The slope of a straight line in Figure 3-12 can be determined using the equation: slope = (y2 - y1)/(x2 - x1). In this case, we are given the options A. ln (C0 - C1), B. t0 - t1, C. C0 - t0, and D. (ln C1 - ln C0)/(t1 - t0).
To determine the slope, we need to identify the values for x and y. Since the equation is not explicitly given and the options provided are not in the form of (y2 - y1)/(x2 - x1), we cannot determine the slope based on the information provided. Therefore, we cannot determine the correct answer option for the slope of the straight line in Figure 3-12.