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Concentrated HCl has a molarity of 12.1 M. How much concentrated HCl is required to make 100.0 mL of a 3.0 M HCl solution?

User Zhm
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Final answer:

To make a 3.0 M HCl solution from a concentrated 12.1 M HCl solution, you will need approximately 24.79 mL of the concentrated solution.

Step-by-step explanation:

To make a 3.0 M HCl solution, you will need to dilute the concentrated 12.1 M HCl solution. The formula for dilution is:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

In this case, C1 = 12.1 M, V1 = ? (unknown), C2 = 3.0 M, and V2 = 100.0 mL. Rearranging the formula, we get:

V1 = (C2 * V2) / C1

Substituting the values, we can calculate the volume of 12.1 M HCl needed to make 100.0 mL of a 3.0 M HCl solution:

V1 = (3.0 M * 100.0 mL) / 12.1 M

V1 = 24.79 mL

So, you will need approximately 24.79 mL of the concentrated HCl solution to make 100.0 mL of a 3.0 M HCl solution.

User Cyrus Zei
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