Question

A spring of negligible mass with a spring of constant of 200.N per meter is stretched 0.2 meter. How much potential energy is stored in the spring?

Answer 1

The potential energy stored in the spring, given a spring constant of 200 N/m and a displacement of 0.2 meters, is calculated using the formula PE = 1/2 k x², which results in 4 Joules of potential energy.

Step-by-step explanation:

The potential energy stored in a spring is calculated using the formula PE = 1/2 k x², where PE is the potential energy, k is the spring constant, and x is the displacement from the spring's rest position. Given that the spring constant k is 200 N/m and the displacement x is 0.2 meters, we substitute these values into the formula to calculate the potential energy stored in the spring.

Using the values given:

PE = 1/2 (200 N/m) (0.2 m)²

PE = 0.5 × 200 × 0.04

PE = 0.5 × 8

PE = 4 Joules

Therefore, the potential energy stored in the spring is 4 Joules.