Final answer:
The diagram that shows the correct relative sizes of the ions in sodium fluoride is A, where Na+ and F- have the same size.
Step-by-step explanation:
The correct answer is A = Na+ and F- same size. The diagram that shows the correct relative sizes of the ions in sodium fluoride is A, where Na+ and F- have the same size. Cations are always smaller than the neutral atom, while anions are always larger. In the case of sodium fluoride, the sodium ion (Na+) and the fluoride ion (F-) have the same size.
This is because the sodium ion has lost one electron to form a closed shell with n=2, while the fluoride ion has gained one electron, resulting in a 3s² valence electron configuration. The diagram that shows the correct relative sizes of the ions in sodium fluoride is A, where Na+ and F- have the same size. Both ions have a nuclear charge of +11, but their electron configurations give them the same size.