Answer:
c. 7/12
Explanation:
There are 36 possible outcomes when you roll a die twice.
11, 12, 13, 14, 15, 16
21, 22, 23, 24, 25, 26
31, 32, 33, 34, 35, 36
41, 42, 43, 44, 45, 46
51, 52, 53, 54, 55, 56
61, 62, 63, 64, 65, 66
The desired outcomes are the ones whose first number is greater than or equal to the second number. They are shown in bold and underline above.
There are 21 desired outcomes.
p(first number ≥ second number) = 21/36 = 7/12
Answer: c. 7/12