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The marching band is holding a fundraiser. The band is selling t-shirts for $22 and yearbooks for $23. The goal is to sell at least $2,400 in merchandise. Which of the following is a solution to this scenario?

User Shauri
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1 Answer

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Final answer:

To find a solution to this scenario, we need to determine how many t-shirts and yearbooks need to be sold in order to reach the goal of at least $2,400 in merchandise. One possible solution would be to sell 100 t-shirts and 9 yearbooks.

Step-by-step explanation:

To find a solution to this scenario, we need to determine how many t-shirts and yearbooks need to be sold in order to reach the goal of at least $2,400 in merchandise. Let x represent the number of t-shirts and y represent the number of yearbooks sold. The total amount of money from t-shirts is 22x and the total amount of money from yearbooks is 23y. We can set up the following equation: 22x + 23y ≥ 2400.

To find one possible solution, we can plug in values for x and solve for y or vice versa. For example, if we let x = 100, we get: 22(100) + 23y ≥ 2400. Simplifying, we have 2200 + 23y ≥ 2400. Subtracting 2200 from both sides, we get 23y ≥ 200. Dividing both sides by 23, we find that y ≥ 8.7. Since y represents the number of yearbooks sold, it must be a whole number, so y = 9. Therefore, selling 100 t-shirts and 9 yearbooks would be one possible solution to this scenario.

User Macleojw
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