Question

Reacting masses

If you have a balanced equation for a reaction, you can calculate the masses of reactants and products.
Sample question
Look at this equation: CaCO3(s) → CaO(s) + CO2(g)
If we have 50g of CaCO3, how much CaO can we make?

Answer 1

To calculate the mass of CaO produced from 50g of CaCO3, we can use the balanced equation and stoichiometry. The mass of CaO is 27.98g.

Step-by-step explanation:

The balanced equation for the reaction is CaCO3(s) → CaO(s) + CO2(g). If we have 50g of CaCO3, we can calculate the mass of CaO using the following steps:

1. Find the molar mass of CaCO3 (calcium carbonate) = 40.08 g/mol (Ca) + 12.01 g/mol (C) + 3(16.00 g/mol) (O) = 100.08 g/mol
2. Convert the given mass of CaCO3 to moles using its molar mass: 50g CaCO3 * (1 mol CaCO3 / 100.08g CaCO3) = 0.4997 mol CaCO3
3. Use the coefficients in the balanced equation to find the moles of CaO produced: 1 mol CaCO3 produces 1 mol CaO, so 0.4997 mol CaCO3 produces 0.4997 mol CaO
4. Finally, convert the moles of CaO to grams using the molar mass of CaO (56.08 g/mol): 0.4997 mol CaO * (56.08 g CaO / 1 mol CaO) = 27.98g CaO

Therefore, if we have 50g of CaCO3, we can make 27.98g of CaO.