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A 30-meter path surrounds a rectangular garden. The width of the garden is two-thirds its length. Find the length and the width.

User Shakira
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Answer: Let's denote the length of the rectangular garden as L and the width as W.

We are given two pieces of information:

1. The perimeter of the rectangular garden plus the surrounding path is 30 meters.

2. The width of the garden is two-thirds its length.

To find the length and width, we can use these two pieces of information and solve the problem using algebraic equations.

Step 1: Express the perimeter in terms of L and W.

The perimeter of the rectangular garden is the sum of all four sides:

Perimeter = 2L + 2W

Step 2: Express the relationship between the width and length.

According to the given information, the width (W) is two-thirds of the length (L):

W = (2/3)L

Step 3: Substitute the width expression into the perimeter equation.

Substituting W = (2/3)L into the perimeter equation:

30 = 2L + 2(2/3)L

Step 4: Simplify and solve for L.

30 = 2L + (4/3)L

Multiplying the entire equation by 3 to eliminate the fraction:

90 = 6L + 4L

Combining like terms:

90 = 10L

Dividing both sides by 10:

L = 9

Step 5: Calculate the width using the relationship between L and W.

W = (2/3)L

W = (2/3)(9)

W = 6

Therefore, the length of the rectangular garden is 9 meters and the width is 6 meters.

Explanation:

User Dkasak
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