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If LM = 6, what is the perimeter of △PKQ?

If LM = 6, what is the perimeter of △PKQ?-example-1

2 Answers

8 votes

Answer:

42

Explanation:

3/(3+x-6)=5/(5+x)

cross multiply

3(5+x)=5(3+x-6)

15+3x=15+5x-30

15+3x=5x-15

15+15=5x-3x

30=2x

x=15

That means KQ=15 and PK=15-6=9. Now we have to find PQ, which is the same as JM. We’ll call that length b.

5/15=6/b

cross multiply

5b=90

b=18

15+9+18=42

User Kasas
by
4.3k points
4 votes

Answer:

KM=LN Given

KM=KL+LM Segment Addition Postulate

LN=LM+MN Segment Addition Postulate

KL+LM=LM+MN Substitution Property of Equality

KL=MN Subtraction Property of Equality this is the formula :)

Explanation:

User Andreas Ka
by
4.5k points