Question

A baseball player runs into the outfield fence trying to catch a fly ball.if he experiences an impulse of -665kg.ms over 0.23s, what was the force the wall exerted on him?

Answer 1

The force exerted by the wall on the baseball player is approximately 2891 N in the opposite direction of the player's initial motion.

Step-by-step explanation:

To determine the force exerted by the wall on the baseball player, we can use the concept of impulse. Impulse is equal to the change in momentum, which can be calculated as the product of the force and the time interval. In this case, the impulse is given as -665 kg·m/s, and the time interval is 0.23 s.

By rearranging the equation for impulse, we can find the force: Force = Impulse / Time interval. Plugging in the values, we get: Force = -665 kg·m/s / 0.23 s. This gives us a force of approximately -2891 N.

The negative sign indicates that the force exerted by the wall is in the opposite direction of the player's motion. Therefore, the force exerted by the wall on the baseball player is approximately 2891 N in the opposite direction of the player's initial motion.