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13. Construct the probability distribution if 3 people have a GPA of 4.0 (A), 7 people have a GPA of 3.0 (B), 5 people have a GPA of 2.0 (C), 4 people with a GPA of 1.0 (D) and 1 person has a GPA of 0.0 (failing).

Find the mean, variance and standard deviation.

User SHS
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1 Answer

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The mean GPA is 2.35.

The variance is 1.2115.

The standard deviation is approximately 1.104.

Probability Distribution

Here's the probability distribution table:

GPA Number of Students Probability

4.0 (A) 3 0.15

3.0 (B) 7 0.35

2.0 (C) 5 0.25

1.0 (D) 4 0.20

0.0 (F) 1 0.05

Mean

To calculate the mean (average GPA), we need to multiply each GPA by its probability and sum the products:

Mean = Σ (GPA * Probability)

Mean = (4.0 * 0.15) + (3.0 * 0.35) + (2.0 * 0.25) + (1.0 * 0.20) + (0.0 * 0.05)

Mean = 0.6 + 1.05 + 0.5 + 0.2 + 0

Mean = 2.35

Therefore, the mean GPA is 2.35.

Variance

To calculate the variance, we need to follow these steps:

Calculate the squared deviation from the mean for each GPA.

Multiply each squared deviation by its probability.

Sum the products obtained in step 2.

Variance = Σ [(GPA - Mean)^2 * Probability]

Variance = [(4.0 - 2.35)^2 * 0.15] + [(3.0 - 2.35)^2 * 0.35] + [(2.0 - 2.35)^2 * 0.25] + [(1.0 - 2.35)^2 * 0.20] + [(0.0 - 2.35)^2 * 0.05]

Variance = (2.7025 * 0.15) + (0.4225 * 0.35) + (0.1225 * 0.25) + (1.7689 * 0.20) + (5.4756 * 0.05)

Variance = 0.4054 + 0.1479 + 0.0306 + 0.3538 + 0.2738

Variance = 1.2115

Therefore, the variance is 1.2115.

Standard Deviation

Finally, to find the standard deviation, we need to take the square root of the variance:

Standard Deviation = √Variance

Standard Deviation = √1.2115

Standard Deviation ≈ 1.104

Therefore, the standard deviation is approximately 1.104.

User Kasdega
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