Question

1) A bag of potato chips is packaged at sea level (1.00 atm) and has a volume of 315 mL. If this bag of chips is transported to Denver (0.82 atm), what will the new volume of the bag be?

Answer 1

384.15 mL

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 1 atm

Initial volume (V₁) = 315 mL

Final pressure (P₂) = 0.82 atm

Final volume (V₂) =?

The new volume (i.e final volume) of the bag can be obtained as follow:

P₁V₁ = P₂V₂

1 × 315 = 0.82 × V₂

315 = 0.82 × V₂

Divide both side by 0.82

V₂ = 315 / 0.82

V₂ = 384.15 mL

Therefore, the new volume of the bag is 384.15 mL

Answer 2

384.15 mL

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 1 atm

Initial volume (V₁) = 315 mL

Final pressure (P₂) = 0.82 atm

Final volume (V₂) =?

The new volume (i.e final volume) of the bag can be obtained as follow:

P₁V₁ = P₂V₂

1 × 315 = 0.82 × V₂

315 = 0.82 × V₂

Divide both side by 0.82

V₂ = 315 / 0.82

V₂ = 384.15 mL

Therefore, the new volume of the bag is 384.15 mL