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A 40g sample of N-16 decays to 10g in 44.4 seconds what is its half life?

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Final answer:

The half-life of N-16 is calculated by dividing the total elapsed time (44.4 seconds) by the number of half-lives to reduce from 40g to 10g, which is 2. The half-life is therefore 22.2 seconds.

Step-by-step explanation:

To determine the half-life of N-16, we start with a 40g sample and note that it decays to 10g in 44.4 seconds.

Because the amount remaining is 1/4 of the original, we have gone through two half-lives.

We can calculate the half-life (T1/2) by dividing the elapsed time by the number of half-lives that have passed, which in this case is 2.

Half-life calculation:

  • Total time elapsed: 44.4 seconds
  • Number of half-lives (n): 44.4 s ÷ T1/2 = 2
  • Solving for T1/2:
  • T1/2 = 44.4 s ÷ 2 =
  • 22.2 seconds

Therefore, the half-life of N-16 is 22.2 seconds.

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