Final answer:
To find the minimum runway length for an airplane's takeoff given an acceleration rate of 3 m/s^2 and a takeoff speed of 65 m/s, the kinematic equation is used, resulting in a minimum runway length of 705.83 meters.
Step-by-step explanation:
To determine the minimum runway length required for a plane to reach takeoff speed with the lowest acceleration rate, we can use the kinematic equation:
d = v2 / (2a)
Where:
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- d is the minimum runway distance,
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- v is the takeoff speed, and
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- a is the acceleration rate.
Given that:
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- The takeoff speed v = 65 m/s,
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- The acceleration rate a = 3 m/s2,
We can calculate the minimum runway distance as follows:
d = (65 m/s)2 / (2 × 3 m/s2)
This gives:
d = 4225 m2/s2 / 6 m/s2
Therefore:
d = 705.83 m
Thus, the minimum runway length should be 705.83 meters.