Final answer:
Using the stoichiometry of the balanced reaction and the molar masses of NaCl and AgCl, it is shown that 58.5 g of NaCl can theoretically produce 143.46 g of AgCl, which is in line with the maximum possible mass of 143.5 g mentioned.
Step-by-step explanation:
To demonstrate that the maximum possible mass of AgCl that can be obtained from 58.5 g of NaCl is 143.5 g, we start by writing the balanced chemical equation for the reaction:
NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq)
We can calculate the moles of NaCl using the formula moles = mass/molar mass.
The molar mass of NaCl is 58.44 g/mol:
moles of NaCl = 58.5 g / 58.44 g/mol
= 1.001 moles of NaCl
According to the balanced equation, 1 mole of NaCl reacts with 1 mole of AgNO3 to form 1 mole of AgCl.
Thus, we can also expect to obtain 1.001 moles of AgCl. The molar mass of AgCl is 143.32 g/mol:
mass of AgCl = 1.001 moles × 143.32 g/mol
= 143.46 g
This calculation shows that 58.5 g of NaCl could produce a maximum of 143.46 g of AgCl, closely matching the provided figure of 143.5 g. This adheres to the stoichiometric relations and the Law of Conservation of Mass.