Question

A solution of sodium chloride reacts with silver nitrate solution to produce a white precipitate of silver chloride. The equation for the reaction is; NaCI(aq) AgNO(aq) → AgCI(s) NaNO:(aq) Show that the maximum possible mass of AgCI that can be obtained from 58.5 g of NaCI is 143.5 g.

Answer 1

Using the stoichiometry of the balanced reaction and the molar masses of NaCl and AgCl, it is shown that 58.5 g of NaCl can theoretically produce 143.46 g of AgCl, which is in line with the maximum possible mass of 143.5 g mentioned.

Step-by-step explanation:

To demonstrate that the maximum possible mass of AgCl that can be obtained from 58.5 g of NaCl is 143.5 g, we start by writing the balanced chemical equation for the reaction:

NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq)

We can calculate the moles of NaCl using the formula moles = mass/molar mass.

The molar mass of NaCl is 58.44 g/mol:

moles of NaCl = 58.5 g / 58.44 g/mol

= 1.001 moles of NaCl

According to the balanced equation, 1 mole of NaCl reacts with 1 mole of AgNO3 to form 1 mole of AgCl.

Thus, we can also expect to obtain 1.001 moles of AgCl. The molar mass of AgCl is 143.32 g/mol:

mass of AgCl = 1.001 moles × 143.32 g/mol

= 143.46 g

This calculation shows that 58.5 g of NaCl could produce a maximum of 143.46 g of AgCl, closely matching the provided figure of 143.5 g. This adheres to the stoichiometric relations and the Law of Conservation of Mass.