Final answer:
The solubility of magnesium carbonate (MgCO3) in pure water can be calculated using its solubility product constant (Ksp). The solubility of MgCO3 is determined to be 1.61 x 10^-4 M.
Step-by-step explanation:
The solubility of a compound can be determined based on its solubility product constant (Ksp). In this case, the Ksp of magnesium carbonate (MgCO3) is given as 2.6 x 10^-9. The Ksp expression for MgCO3 is:
Ksp = [Mg2+][CO3^2-]
Since MgCO3 dissolves into magnesium ions (Mg2+) and carbonate ions (CO3^2-), we can assume that their concentrations are equal. Let's call the solubility of MgCO3 's'
Ksp = s x s = s^2
By substituting the given Ksp value into the expression, we get:
s^2 = 2.6 x 10^-9
To find the solubility (s), we can take the square root of both sides:
s = sqrt(2.6 x 10^-9) = 1.61 x 10^-4
Therefore, the solubility of MgCO3 in pure water is 1.61 x 10^-4 M.