Final answer:
To find the percent of water in CuSO4*7 H2O, we can calculate the ratio of water molecules to the total mass of the compound. CuSO4*7 H2O is a hydrate, meaning it contains water molecules. By using the molar masses of CuSO4 and H2O, we can determine that the percent of water in CuSO4*7 H2O is approximately 99.13%.
Step-by-step explanation:
To find the percent of water in CuSO4*7 H2O, we need to determine the ratio of water molecules to the total mass of the compound. CuSO4*7 H2O is a hydrate, which means it contains water molecules. In this case, there are 7 water molecules associated with each formula unit of CuSO4.
To calculate the percent of water, we need to know the molar mass of CuSO4 and H2O. The molar mass of CuSO4 is 159.62 g/mol and the molar mass of H2O is 18.02 g/mol.
Now, we can calculate the percent of water:
Percent of water = (7 * 18.02 g/mol) / (159.62 g/mol + 7 * 18.02 g/mol) * 100%
Percent of water = (126.14 g/mol) / (127.24 g/mol) * 100%
Percent of water ≈ 99.13%