Question

Let t(x)=16x2–4x–9 and w(x)=5x–10.5. Find the following values. Write each answer as an integer, decimal, or simplified fraction. t(0.5) = w(2)Let t(x)=16x2–4x–9 and w(x)=5x–10.5. Find the following values. Write each answer as an integer, decimal, or simplified fraction. t(0.5) = w(2)

Answer 1

To solve for t(0.5), substitute x in the function t(x) and calculate, yielding a result of -3. Similarly, substitute x in the function w(x) to find w(2), resulting in -0.5.

Step-by-step explanation:

To find the value of t(0.5), substitute x with 0.5 in the function t(x)=16x2–4x–9, and to find the value of w(2), substitute x with 2 in the function w(x)=5x–10.5.

For t(0.5), the calculation is as follows:

t(0.5) = 16(0.5)2 – 4(0.5) – 9 = 16(0.25) – 2 – 9 = 4 – 2 – 9 = –3

For w(2), the calculation is:

w(2) = 5(2) – 10.5 = 10 – 10.5 = –0.5