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3. A stone that starts at rest is in free fall for 8.0 s.

(a) Calculate the stone’s velocity after 8.0 s.
(b) What is the stone’s height covered during this time?

User Eolith
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1 Answer

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Final answer:

The stone's final velocity after free falling for 8 seconds is 78.4 m/s, and the height covered during this time is 313.6 meters.

Step-by-step explanation:

To calculate the stone’s velocity after it is in free fall for 8.0 seconds, we can use the equation of motion for an object under constant acceleration due to gravity:

Calculating Velocity

The equation to use is v = gt, where ‘v’ is the velocity, ‘g’ is the acceleration due to gravity (9.8 m/s²), and ‘t’ is the time in seconds. For complete 8 seconds of free fall, the stone's velocity (v) can be calculated as:

v = 9.8 m/s² * 8 s = 78.4 m/s

Calculating Height Covered

To calculate the height covered during this time, we can use the equation s = ut + ½gt², where ‘s’ is the distance, ‘u’ is the initial velocity (0 m/s since it starts at rest), and ‘t’ is the time. Therefore, the height covered is:

s = 0 m/s * 8 s + ½ * 9.8 m/s² * (8 s)² = ½ * 9.8 m/s² * 64 s² = 313.6 m

User Jashim
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