The measures for the angles of the square ABCD with diagonals AC and BD are:
m∠ADB = 45°
m∠AEB = 90°
m∠ACB = 45°
The opposite sides of a square are equal and its diagonals bisect each other at 90°.
The angle m∠ADB is equal to m∠ACB and they both have the measure of 45° which is half the angle 90° at D and C of the square respectively.
m∠ADB = m∠ADC/2
m∠ADC = 90°
m∠ADB = 90°/2
m∠ADB = 45°
Lines AC and BD are the diagonals of the square ABCD and they also bisect the angle 90° at A, B, C and D, which implies that; m∠AEB = 90°
m∠ACB = 11x - 32
recall that m∠ADB is equal to m∠ACB
11x - 32 = 45°
11x = 45 + 32
x = 77/11
x = 7.
Therefore, the measure 45° is for the angles m∠ADB and m∠ACB while m∠AEB have a measure of 90°.