Proof that AD || CB:
Given: AB 1 BD, BD 1 DC, LA = ∠C
Prove: AD || CB
Proof:
Since AB 1 BD, ∠ABD = 180° - ∠AB = ∠DAB (alternate interior angles) (Image 1)
Similarly, since BD 1 DC, ∠BDC = 180° - ∠BD = ∠CDB (alternate interior angles) (Image 1)
Since LA = ∠C, ∠DAB + ∠BDC = 180° (same side interior angles) (Image 1)
Substituting equations 1 and 2 into equation 3, we get:
(∠ABD + ∠BDC) = 180°
(180° - ∠AB) + (180° - ∠BD) = 180°
360° - ∠AB - ∠BD = 180°
∠AB + ∠BD = 360° - 180°
∠AB + ∠BD = 180°
Since ∠AB + ∠BD = 180°, AD || CB (supplementary angles) (Image 1)
Therefore, AD || CB.