Question

A teenager has a car that accelerates at 3m/s^2 and decelerates at 4.5m/s^2 on a trip to store; he accelerates from rest to , drives 3m/s^2at a constant speed for 5 sec, and then comes to a momentary stop at a corner.He then accelerates to18m/s , drives at a constant speed for 20 sec, decelerates 8/3 sec, continuous for 4 sec at this speed and then comes to stop. a) How long does the trip take

Answer 1

The total time for the trip is 36 seconds.

Step-by-step explanation:

The total time for the trip can be calculated by adding the times spent during each segment of the trip.

• The time to accelerate from rest to 3 m/s is given by:
• t1 = v / a = 3 m/s / 3 m/s2 = 1 second
• The time spent driving at a constant speed of 3 m/s for 5 seconds is:
• t2 = 5 seconds
• The time to accelerate from rest to 18 m/s is:
• t3 = v / a = 18 m/s / 3 m/s2 = 6 seconds
• The time spent driving at a constant speed of 18 m/s for 20 seconds is:
• t4 = 20 seconds
• The time to decelerate from 18 m/s to rest is given by:
• t5 = v / a = 18 m/s / 4.5 m/s2 = 4 seconds

The total time for the trip is calculated by adding the times for each segment: ttotal = t1 + t2 + t3 + t4 + t5 = 1 + 5 + 6 + 20 + 4 = 36 seconds.