Final answer:
To calculate the heat needed to raise the temperature of 12.0 g of water from 20°C to 100°C, we use the specific heat capacity equation, resulting in 4017.6 joules required.
Step-by-step explanation:
To calculate the heat (q) required to raise the temperature of water, we can use the specific heat capacity equation: q = mcΔT, where:
- m is the mass of the water,
- c is the specific heat capacity of water,
- ΔT is the change in temperature.
In this case, the mass (m) of the water is 12.0 g, the specific heat capacity (c) is 4.184 J/g°C, and the change in temperature (ΔT) is 80°C (from 20°C to 100°C).
Using the equation:
q = mcΔT
q = (12.0 g)(4.184 J/g°C)(80°C)
q = 4017.6 J
Therefore, 4017.6 joules of heat is required to heat 12.0 g of water from 20°C to 100°C.